Gujarati
Hindi
14.Waves and Sound
normal

For a certain organ pipe three successive resonance frequencies are observed at $425\, Hz,595 \,Hz$ and $765 \,Hz$ respectively. If the speed of sound in air is $340 \,m/s$,  then the length of the pipe is ..... $m$

A

$2$

B

$0.4$

C

$1$

D

$0.2$

Solution

$425: 595: 765=5: 7: 9$

hence it is a closed organ pipe

$\frac{5 \mathrm{V}}{4 l}=425 \Rightarrow l=\frac{5 \times 340}{4 \times 425}=1 \mathrm{\,m}$

Standard 11
Physics

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