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14.Waves and Sound
normal
For a certain organ pipe three successive resonance frequencies are observed at $425\, Hz,595 \,Hz$ and $765 \,Hz$ respectively. If the speed of sound in air is $340 \,m/s$, then the length of the pipe is ..... $m$
A
$2$
B
$0.4$
C
$1$
D
$0.2$
Solution
$425: 595: 765=5: 7: 9$
hence it is a closed organ pipe
$\frac{5 \mathrm{V}}{4 l}=425 \Rightarrow l=\frac{5 \times 340}{4 \times 425}=1 \mathrm{\,m}$
Standard 11
Physics